(x-1)^2=x(x-4)+8

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Solution for (x-1)^2=x(x-4)+8 equation: 



(x-1)^2=x(x-4)+8

We move all terms to the left:

(x-1)^2-(x(x-4)+8)=0



We calculate terms in parentheses: -(x(x-4)+8), so:

x(x-4)+8

We multiply parentheses

x^2-4x+8

Back to the equation:

-(x^2-4x+8)



We get rid of parentheses

-x^2+(x-1)^2+4x-8=0

We add all the numbers together, and all the variables

-1x^2+4x+(x-1)^2-8=0

We move all terms containing x to the left, all other terms to the right

-1x^2+4x+(x-1)^2=8

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